How can I check if a service exists from Python?

asked 2017-06-01 12:30:27 -0600

BJP
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updated 2017-06-01 13:37:19 -0600

This question has an answer for roscpp; what is the equivalent solution for Python?

EDIT: I do not want to wait for the service. I want to take one action if the service exists and a different action if it doesn't exist.

A hack might be to wrap a wait_for_service call in a try/catch to catch a ROSException and verify that that ROSException was a timeout, but that's very ugly and I'm not sure what the minimum required timeout should be to ensure that extant topics do not cause the Exception.

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answered 2017-06-02 00:59:25 -0600

Zubin Priyansh
161 ●3 ●4 https://blackcoffeerob...

updated 2017-06-03 04:14:33 -0600

There is a function in the rospy API to get a list of services: http://docs.ros.org/kinetic/api/rospy...

I guess this would return a list of all registered services and you could check if the service you are waiting for is in this list.

Edit: I haven't tested the API call I linked in the original answer. I used http://docs.ros.org/kinetic/api/rospy...

It works for me:

>>> import rosservice
>>> service_list = rosservice.get_service_list()
>>> print service_list
['/rosout/set_logger_level', '/rosout/get_loggers']

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Have you tried this?

NEngelhard ( 2017-06-03 03:48:14 -0600 )edit

@NEngelhard I had successfully gotten a list of services in rospy, but now I realize it wasn't with this particular API call. I used this call: http://docs.ros.org/kinetic/api/rosse... . I should edit my answer accordingly.

Zubin Priyansh ( 2017-06-03 04:10:13 -0600 )edit

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answered 2017-06-01 12:43:19 -0600

NEngelhard
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updated 2017-06-01 12:43:55 -0600

Please at least read the wiki page (wiki.ros: Services) before opening a question here. The section

"(...) Wait until a service becomes available. You can optionally specify a timeout (in seconds) to wait for, in which case a ROSException is raised if the timeout is exceeded."

is hard to miss.

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That doesn't answer the question. I want to take one action if a service is available and a different action if the service is not available.

BJP ( 2017-06-01 13:33:59 -0600 )edit

Why do you think that the approach is "very ugly"? If you want to speed up the test, you still can look at the implementation and use the rosgraph.Master directly.

NEngelhard ( 2017-06-01 13:54:17 -0600 )edit

It's very ugly for (at least) three reasons: 1) that's not what wait_for_service is designed to do, 2) it's bad practice to catch an exception in unexceptional circumstances (when no error has occurred), and 3) the timeout duration selection issue.

BJP ( 2017-06-01 14:23:05 -0600 )edit

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How can I check if a service exists from Python?

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