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roslaunch default package

asked 2014-06-19 12:03:57 -0600

crpizarr gravatar image

In a .launch file inside a package, is it possible to omit the package name in a <node> tag if the node package is the same as the package the launcher lives in? I mean, I have a launcher with lines like this:

<launch>

<rosparam command="load" file="$(find my_package)/config/config.yaml" ns="configuration" />

<node pkg="my_package" name="node1" type="node1.py" output="screen" />

<node pkg="my_package" name="node2" type="node2.py" output="screen" />

<node pkg="my_package" name="node3" type="node3.py" output="screen" />

<node pkg="my_package" name="gui" type="gui.py" output="screen" required="true"/>

</launch>

If I want to change the package's name, I'll have to change the pkg argument of all the nodes. Is there a way to omit that, or at least to replace with something like "this" (or "self", as Python programmers use)?

Thanks

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Comments

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My guess is no and if it was available I'd advise against it. If someone copies the launch to adapt it, everything will break. Changing all occurrences is an easy task for search and replace.

dornhege gravatar image dornhege  ( 2014-06-19 12:14:02 -0600 )edit

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answered 2014-06-19 23:18:28 -0600

fergs gravatar image

You could use roslaunch args, but I would completely advise against that. Changing the name of a package is not something to be taken lightly, as it affects all downstream uses (roslaunch files, packages that find this package through catkin, dependency calculations, etc).

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Asked: 2014-06-19 12:03:57 -0600

Seen: 269 times

Last updated: Jun 19 '14