Failed converting xacro to urdf
When I run the command rosrun xacro xacro.py ur5.urdf.xacro > ur5.urdf, the result is not as good as I expected.
<robot xmlns:xacro="http://www.ros.org/wiki/xacro"> </robot>
1
This is indeed the cause. ur5.urdf.xacro is not a top-level xacro, but only defines a macro. The ur5_robot.urdf.xacro is the one instantiating the model, and should those be used.
See also universal_robot#288.
-Code: "rosrun xacro xacro --inorder -o E:\work\universal_robot-kinetic-devel\ur_description\urdf\ur5_robot.urdf E:\work\universal_robot-kinetic-devel\ur_description\urdf\ur5_robot.urdf.xacro"
-Error: "xacro: in-order processing became default in ROS Melodic. You can drop the option. ←[91mresource not found: ur_description ROS path [0]=c:\opt\ros\noetic\x64\share\ros ROS path [1]=c:\opt\ros\noetic\x64\share←[0m when processing file: E:\work\universal_robot-melodic-devel\ur_description\urdf\ur10_robot.urdf.xacro"
Can someone help me?
Could I please ask you to not cross-post questions like these to both ROS Answers and the package's issue tracker (universal_robot#288)? Besides bad etiquette, it leads to duplication of effort and reduced visibility of solutions.
Thanks for your kind remainder. I published this issue here firstly, then I think Universal_robot is the more suitable category, so I pulbished a second time. Sorry for my mistake and I will pay attention to your advice. Thanks.